## Sunday, November 28, 2010

### C Program For Fibonacci Series

Hello everybody I want to discuss about How to generate a Fibonacci series in C programming. ### What is Fibonacci Series?

The first two Fibonacci numbers are 0 and 1 then next number is addition of previous two numbers.

0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89.....
In mathematics it is defined by recurrence relation.

### Program Code

`  //C Program for generate Fibonacci series#include "stdio.h"#include "conio.h"void main(){ int a,b,c,i,n; clrscr(); a=0; b=1; printf("\n enter n for how many times generate series"); scanf("%d",&n); printf("\n FIBONACCI SERIES\n"); printf("\t%d\t%d",a,b);for(i=0;i<n;i++){     c=a+b;     a=b;     b=c;     printf("\t%d",c); } getch();}`

### Input\Output susamoy said...

thanks....... Anonymous said...
This comment has been removed by the author. Anonymous said...

thanks

raviteja said...

can u write this program without taking 0,1 as initial values for a and b variables

shabha said...

wrong!!!!!

shabha said...

u hav printed 8 no's bt v ned only 6 no's???

Manigandan said...

if you take
a=-1
b=1
means u don't need to print a,b

swati said...

wow thanks its totally right :)

abhi said...

mind blowing its right

aravind said...

thanku

newB1e said...

dis is wrong dude ;
when u want 3rd number in the series (dat is 1) you hav to give value of n == 1...

Gagan said...

I hope this solves your problem
#include
#include
void main()
{
int a,b,c,i,n;
a=0;
b=1;
printf("Enter number of terms of the series to be generated:");
scanf("%d",&n);
if(n==1)
{
printf("\n FIBONACCI SERIES\n");
printf("%d",a);

}
else if(n==2)
{
printf("\n FIBONACCI SERIES\n");
printf("%d\t%d",a,b);

}
else
{
printf("%d\t%d",a,b);
for(i=3;i<=n;i++)
{
c=a+b;
a=b;
b=c;
printf("\t%d",c);

}
}
getch();
}

akshay76 said...

void main()
{
int a,b,c,i,n;
a=0;
b=1;
printf("Enter number of terms of the series to be generated:");
scanf("%d",&n);
if(n==1)
{
printf("\n FIBONACCI SERIES\n");
printf("%d",a);

}
else if(n==2)
{
printf("\n FIBONACCI SERIES\n");
printf("%d\t%d",a,b);

}
else
{
printf("%d\t%d",a,b);
for(i=3;i<=n;i++)
{
c=a+b;
a=b;
b=c;
printf("\t%d",c);

}
}
getch();
}

OR

void main()
{
int a,b,c,i,n;
clrscr();
a=0;
b=1;
printf("\n enter n for how many times generate series");
scanf("%d",&n);
printf("\n FIBONACCI SERIES\n");
printf("\t%d\t%d",a,b);
for(i=0;i<n;i++)
{
c=a+b;
a=b;
b=c;
printf("\t%d",c);
}
getch();
}

naveen said...

well, the for loop should be
for(i=1;i<=n-2;i++)

Subin Priyan said...

good one re, thank you

priyan said...

thanks..

M Ay said...

Thanks!!!!!!!!!!!
void main()
{
int a,b,c,i,n;
clrscr();
a=0;
b=1;
printf("\n enter n for how many times generate series");
scanf("%d",&n);
printf("\n FIBONACCI SERIES\n");
printf("\t%d\t%d",a,b);
for(i=0;i<n;i++)
{
c=a+b;
a=b;
b=c;
printf("\t%d",c);
}
getch();
}

mahabub & sayan said...

this is the best.........

#include
#include
void main()
{
int a,b,c,i,n;
clrscr();
a=0;
b=1;
printf("\n enter n for how many times generate series");
scanf("%d",&n);
printf("\n FIBONACCI SERIES\n");
printf("\t%d\t%d",a,b);
for(i=1;i<n;i++)
{
c=a+b;
a=b;
b=c;
printf("\t%d",c);
}
getch();
}

ZuBaiR said...

hey can u post flow chart for this !!! plzz

Lavish said...

fibonacci series starts with 1 never with 0...

DHIVYA. said...
This comment has been removed by the author.
DHIVYA. said...

Thank you.

Arjit Sharma said...

a= -1

b=1

sum = a+b

a=b

b=sum

Unknown said...

fibonacci series
#include
#include
void main()
{
int i,n,c,a=0,b=1;
clrscr();
printf("enter the number");
scanf("\n%d\n",&n);
printf("\nFIBONACCI SERIES\n");
printf(%d\n%d\n",a,b);
for(i=3;i<=n;i++)
{
c=a+b;
a=b;
b=c;
printf("%d\n",c);
}
getch();
}

sonam said...

thank u..

karam said...

can explain the running of loop?

Varun said...

//This program will print the fibonacci series by using the printf statement only once...have a close look!!!

fibonacci series
#include
#include
void main()
{
int i,n,c,a=0,b=1;
clrscr();
printf("enter the number");
scanf("\n%d\n",&n);
printf("\nFIBONACCI SERIES\n");

for(i=0;i<=n;i++)
{
printf("%d\n",a);
c=a+b;
a=b;
b=c;

}
getch();
}

mudit said...

can anyone tell how to write reverse fabonnaci series

M Junaid Awan. said...

#include
#include
void main()
{
int i,n,c,a=0,b=1;
clrscr();
printf("enter the number");
scanf("\n%d\n",&n);
printf("\nFIBONACCI SERIES\n");

for(i=n;i<n;i--)
{
printf("%d\n",a);
c=a+b;
a=b;
b=c;

}
getch();
}

Arnab said...

idiot

making it complex

snigdho1993 said...

It's running successfully.......... thanks..

Unknown said...
This comment has been removed by the author.
Unknown said...

#include

main()
{
int n, first = 0, second = 1, next, c;

printf("Enter the number of terms\n");
scanf("%d",&n);

printf("First %d terms of Fibonacci series are :-\n",n);

for ( c = 0 ; c < n ; c++ )
{
if ( c <= 1 )
next = c;
else
{
next = first + second;
first = second;
second = next;
}
printf("%d\n",next);
}

return 0;
}

Unknown said...

Hey Frnz I Have Simple Way To Print it And Hope u Like N try it
so let's begin

void main(){

int a,b,i,n;

clrscr();

n=10;

a=0;

b=1;

for(i=1; i<=n; i++){

a=a+b;

b=a-b;

printf("%d ",b);

}

getch();}

the value of 'n' Will Varies as the series wants to maximize

abhay said...

hi, u have oversimplified...

the series is 0,1,1,2,3,5,8... while ur program gives
0,1,2,3,5,8....
so the third term gets missing...
but good attempt....

i think it is best to use
for(couter=1;counter<=N-2;counter++) loop....
:-)

Unknown said...

the program is wrong.. publish the correct coding;;;;

Unknown said...

u have to give for loop as for(i=2;i<n;i++)
remaining thnks are ok................

Unknown said...

/* Fibonacci Series c language */
#include

main()
{
int n,a=0,b=1,c,d;
printf("Enter the number of terms\n");
scanf("%d",&n);
printf("First %d terms of Fibonacci series are :-\n",n);
for(d=0;d<n;d++)
{
if (d<=1)
c=d;
else
{
c=a+b;
a=b;
b=c;
}
printf("%d\n",c);
}
getch();
}

Unknown said...

Other way without using "if else"

/* Fibonacci Series c language */
#include

main()
{
int n,a=0,b=1,c,d;

printf("Enter the number of terms\n");
scanf("%d",&n);
printf("First %d terms of Fibonacci series are :- \n",n);
printf("%d\n%d\n",a,b);

for(d=0;d<n-2;d++)
{
c=a+b;
a=b;
b=c;

printf("%d\n",c);
}
getch();
}

Unknown said...

/* Fibonacci Series c language */
#include

main()
{
int n,a=0,b=1,c,d;

printf("Enter the number of terms\n");
scanf("%d",&n);
printf("First %d terms of Fibonacci series are :- \n",n);
printf("%d\n%d\n",a,b);

for(d=0;d<n-2;d++)
{
c=a+b;
a=b;
b=c;

printf("%d\n",c);
}
getch();
}

Unknown said...

if i enter the no 1 than it will print 0 and 1 both in place of zero
i think it's not proper output

slyVESter said...

All above programs are starting with 0 and 1, what if we want another values say -1 or other integer ? Try this one !
#include
#include
int main(void)
{
int a,b,c,i,n;
printf("Enter first number: ");
scanf("%d", &a);
printf("\nEnter the second number:");
scanf("%d", &b);
printf("\nHow many times does you want the series:");
scanf("%d",&n);
if(n==1)
{
printf("\nFibonacci series is:\t%d", a);
}
else if(n==2)
{
printf("\nFibonacci series is:\t%d\t%d", a,b);
}
else
{
printf("\nFibonacci series is:\t%d\t%d", a,b);
for(i=2; i<n; i++)
{
c= a+b;
a= b;
b= c;
printf("\t%d", c);
}
}
getch();
}

Unknown said...
This comment has been removed by the author.
Unknown said...

#include
main()
{
int i,n,a,b;
printf("enter n terms");
scanf("%d",&n);
printf("fibonacci siries\n");
for(i=0;i<n;i++)
{
a=a+b;
b=a+b;
printf("%d %d",a,b);
}
}

ash said...

Its simplest n perfect code...!!!

TakNeh said...

int main()
{
int a, b, fib, n=10,i;

a=0;b=1;

for (i=0;i<n;i++)
{
printf("fib %d\n", a);
fib = a+b;
a=b;
b=fib;
}
return 0;
}

Unknown said...

#include
#include
void main()
{
int a,b,c,i,n;
a=0;
b=1;
printf("Enter number :");
scanf("%d",&n);
if(n==1)
{
printf("\n fibonacci series\n");
printf("%d",a);

}
else if(n==2)
{
printf("\n fibonacci series\n");
printf("%d\t%d",a,b);

}
else
{
printf("%d\t%d",a,b);
for(i=3;i<=n;i++)
{
c=a+b;
a=b;
b=c;
printf("\t%d",c);

}
}
getch();
}

SUNDAR said...

for(i=0;i<n-2;i++)

SUNDAR said...

Jst Change the for loop

for(i=0;i<n-2;i++)

harish said...

#include
void main()
{ int n,i,a,b,c;
printf("enter the range");
scanf ("%d",&n);
for(i=o;i<=n;i++)
{c=a+b;
a=b;
b=c;
printf("the fibonaci series is=%d",c)
}
getch();
}

Unknown said...

logic is correct and simple but it's not working.

Prasun said...

void main()
{
int a=-1,b=1,c,i;
scanf("%d",&n);
for(i=0;i<n;i++)
{
c=a+b;
a=b;
b=c;
printf("%d\t",c);
}
getch()
}

Unknown said...

#include
#include
main()
{int a,b,i,n;
a=b=1;
printf("enter number of times u want to print fibb series");
scanf("%d",&n);
for(i=0;i<n;i++)
{if(i<=1)
printf("%d",1);
c=a+b;
a=b;
b=c;
printf("%d",c);
}
getch();
}

it will print

1 1 2 3 5 7 12 19.....

Unknown said...

No we can't write this code without intiala'n.

Unknown said...

void main()
{
int i,n;
clrscr();
printf("\n enter n for how many times generate series");
scanf("%d",&n);
printf("\n FIBONACCI SERIES\n");
for(i=0;i<n;i++)
{
cout<<fabo(i)<<" ";
}
getch();
}

fabo(n)
{
if(n==0)
return 0;
if(n==1)
return 1;
else
return fabo(n-1)+fabo(n-2);
}
}

Akash said...

I dont know if u right...but what we were taught was starting from zero itself...well maybe u r right....lets see....

Unknown said...

#include
void main(){
int no,x=1,y=1,z,i;
printf("Enter number :");
scanf("%d",&no);
for(i=2;i<no;i++)
{
z=x+y;
x=y;
y=x;
}
printf("%d",Z);
getch();
}

}

Vishal Mahato said...
This comment has been removed by the author.
Vishal Mahato said...

chek out this as well : c program to find fibonacci series using recursion