What is Fibonacci Series?
The first two Fibonacci numbers are 0 and 1 then next number is addition of previous two numbers.
0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89.....
In mathematics it is defined by recurrence relation.
Program Code
//C Program for generate Fibonacci series
#include "stdio.h"
#include "conio.h"
void main()
{
int a,b,c,i,n;
clrscr();
a=0;
b=1;
printf("\n enter n for how many times generate series");
scanf("%d",&n);
printf("\n FIBONACCI SERIES\n");
printf("\t%d\t%d",a,b);
for(i=0;i<n;i++)
{
c=a+b;
a=b;
b=c;
printf("\t%d",c);
}
getch();
}
Input\Output
thanks.......
ReplyDeleteThis comment has been removed by the author.
ReplyDeletethanks
ReplyDeletecan u write this program without taking 0,1 as initial values for a and b variables
ReplyDeletewrong!!!!!
ReplyDeleteu hav printed 8 no's bt v ned only 6 no's???
ReplyDeletefor(i=0;i<n-2;i++)
Deleteif you take
ReplyDeletea=-1
b=1
means u don't need to print a,b
wow thanks its totally right :)
ReplyDeletemind blowing its right
ReplyDeletethanku
ReplyDeletedis is wrong dude ;
ReplyDeletewhen u want 3rd number in the series (dat is 1) you hav to give value of n == 1...
I hope this solves your problem
ReplyDelete#include
#include
void main()
{
int a,b,c,i,n;
a=0;
b=1;
printf("Enter number of terms of the series to be generated:");
scanf("%d",&n);
if(n==1)
{
printf("\n FIBONACCI SERIES\n");
printf("%d",a);
}
else if(n==2)
{
printf("\n FIBONACCI SERIES\n");
printf("%d\t%d",a,b);
}
else
{
printf("%d\t%d",a,b);
for(i=3;i<=n;i++)
{
c=a+b;
a=b;
b=c;
printf("\t%d",c);
}
}
getch();
}
idiot
Deletemaking it complex
/* Fibonacci Series c language */
Delete#include
main()
{
int n,a=0,b=1,c,d;
printf("Enter the number of terms\n");
scanf("%d",&n);
printf("First %d terms of Fibonacci series are :- \n",n);
printf("%d\n%d\n",a,b);
for(d=0;d<n-2;d++)
{
c=a+b;
a=b;
b=c;
printf("%d\n",c);
}
getch();
}
if i enter the no 1 than it will print 0 and 1 both in place of zero
Deletei think it's not proper output
void main()
ReplyDelete{
int a,b,c,i,n;
a=0;
b=1;
printf("Enter number of terms of the series to be generated:");
scanf("%d",&n);
if(n==1)
{
printf("\n FIBONACCI SERIES\n");
printf("%d",a);
}
else if(n==2)
{
printf("\n FIBONACCI SERIES\n");
printf("%d\t%d",a,b);
}
else
{
printf("%d\t%d",a,b);
for(i=3;i<=n;i++)
{
c=a+b;
a=b;
b=c;
printf("\t%d",c);
}
}
getch();
}
OR
void main()
{
int a,b,c,i,n;
clrscr();
a=0;
b=1;
printf("\n enter n for how many times generate series");
scanf("%d",&n);
printf("\n FIBONACCI SERIES\n");
printf("\t%d\t%d",a,b);
for(i=0;i<n;i++)
{
c=a+b;
a=b;
b=c;
printf("\t%d",c);
}
getch();
}
well, the for loop should be
ReplyDeletefor(i=1;i<=n-2;i++)
good one re, thank you
ReplyDeletethanks..
ReplyDeleteThanks!!!!!!!!!!!
ReplyDeletevoid main()
{
int a,b,c,i,n;
clrscr();
a=0;
b=1;
printf("\n enter n for how many times generate series");
scanf("%d",&n);
printf("\n FIBONACCI SERIES\n");
printf("\t%d\t%d",a,b);
for(i=0;i<n;i++)
{
c=a+b;
a=b;
b=c;
printf("\t%d",c);
}
getch();
}
this is the best.........
ReplyDelete#include
#include
void main()
{
int a,b,c,i,n;
clrscr();
a=0;
b=1;
printf("\n enter n for how many times generate series");
scanf("%d",&n);
printf("\n FIBONACCI SERIES\n");
printf("\t%d\t%d",a,b);
for(i=1;i<n;i++)
{
c=a+b;
a=b;
b=c;
printf("\t%d",c);
}
getch();
}
hey can u post flow chart for this !!! plzz
ReplyDeletefibonacci series starts with 1 never with 0...
ReplyDeleteThis comment has been removed by the author.
ReplyDeleteThank you.
ReplyDeletea= -1
ReplyDeleteb=1
sum = a+b
a=b
b=sum
fibonacci series
ReplyDelete#include
#include
void main()
{
int i,n,c,a=0,b=1;
clrscr();
printf("enter the number");
scanf("\n%d\n",&n);
printf("\nFIBONACCI SERIES\n");
printf(%d\n%d\n",a,b);
for(i=3;i<=n;i++)
{
c=a+b;
a=b;
b=c;
printf("%d\n",c);
}
getch();
}
thank u..
ReplyDeletecan explain the running of loop?
ReplyDelete//This program will print the fibonacci series by using the printf statement only once...have a close look!!!
ReplyDeletefibonacci series
#include
#include
void main()
{
int i,n,c,a=0,b=1;
clrscr();
printf("enter the number");
scanf("\n%d\n",&n);
printf("\nFIBONACCI SERIES\n");
for(i=0;i<=n;i++)
{
printf("%d\n",a);
c=a+b;
a=b;
b=c;
}
getch();
}
hi, u have oversimplified...
Deletethe series is 0,1,1,2,3,5,8... while ur program gives
0,1,2,3,5,8....
so the third term gets missing...
but good attempt....
i think it is best to use
for(couter=1;counter<=N-2;counter++) loop....
:-)
can anyone tell how to write reverse fabonnaci series
ReplyDelete#include
Delete#include
void main()
{
int i,n,c,a=0,b=1;
clrscr();
printf("enter the number");
scanf("\n%d\n",&n);
printf("\nFIBONACCI SERIES\n");
for(i=n;i<n;i--)
{
printf("%d\n",a);
c=a+b;
a=b;
b=c;
}
getch();
}
It's running successfully.......... thanks..
ReplyDeleteThis comment has been removed by the author.
ReplyDelete#include
ReplyDeletemain()
{
int n, first = 0, second = 1, next, c;
printf("Enter the number of terms\n");
scanf("%d",&n);
printf("First %d terms of Fibonacci series are :-\n",n);
for ( c = 0 ; c < n ; c++ )
{
if ( c <= 1 )
next = c;
else
{
next = first + second;
first = second;
second = next;
}
printf("%d\n",next);
}
return 0;
}
Hey Frnz I Have Simple Way To Print it And Hope u Like N try it
ReplyDeleteso let's begin
void main(){
int a,b,i,n;
clrscr();
n=10;
a=0;
b=1;
for(i=1; i<=n; i++){
a=a+b;
b=a-b;
printf("%d ",b);
}
getch();}
the value of 'n' Will Varies as the series wants to maximize
Its simplest n perfect code...!!!
Deletethe program is wrong.. publish the correct coding;;;;
ReplyDeleteu have to give for loop as for(i=2;i<n;i++)
ReplyDeleteremaining thnks are ok................
/* Fibonacci Series c language */
ReplyDelete#include
main()
{
int n,a=0,b=1,c,d;
printf("Enter the number of terms\n");
scanf("%d",&n);
printf("First %d terms of Fibonacci series are :-\n",n);
for(d=0;d<n;d++)
{
if (d<=1)
c=d;
else
{
c=a+b;
a=b;
b=c;
}
printf("%d\n",c);
}
getch();
}
Other way without using "if else"
Delete/* Fibonacci Series c language */
#include
main()
{
int n,a=0,b=1,c,d;
printf("Enter the number of terms\n");
scanf("%d",&n);
printf("First %d terms of Fibonacci series are :- \n",n);
printf("%d\n%d\n",a,b);
for(d=0;d<n-2;d++)
{
c=a+b;
a=b;
b=c;
printf("%d\n",c);
}
getch();
}
All above programs are starting with 0 and 1, what if we want another values say -1 or other integer ? Try this one !
ReplyDelete#include
#include
int main(void)
{
int a,b,c,i,n;
printf("Enter first number: ");
scanf("%d", &a);
printf("\nEnter the second number:");
scanf("%d", &b);
printf("\nHow many times does you want the series:");
scanf("%d",&n);
if(n==1)
{
printf("\nFibonacci series is:\t%d", a);
}
else if(n==2)
{
printf("\nFibonacci series is:\t%d\t%d", a,b);
}
else
{
printf("\nFibonacci series is:\t%d\t%d", a,b);
for(i=2; i<n; i++)
{
c= a+b;
a= b;
b= c;
printf("\t%d", c);
}
}
getch();
}
This comment has been removed by the author.
ReplyDelete#include
ReplyDeletemain()
{
int i,n,a,b;
printf("enter n terms");
scanf("%d",&n);
printf("fibonacci siries\n");
for(i=0;i<n;i++)
{
a=a+b;
b=a+b;
printf("%d %d",a,b);
}
}
int main()
ReplyDelete{
int a, b, fib, n=10,i;
a=0;b=1;
for (i=0;i<n;i++)
{
printf("fib %d\n", a);
fib = a+b;
a=b;
b=fib;
}
return 0;
}
#include
ReplyDelete#include
void main()
{
int a,b,c,i,n;
a=0;
b=1;
printf("Enter number :");
scanf("%d",&n);
if(n==1)
{
printf("\n fibonacci series\n");
printf("%d",a);
}
else if(n==2)
{
printf("\n fibonacci series\n");
printf("%d\t%d",a,b);
}
else
{
printf("%d\t%d",a,b);
for(i=3;i<=n;i++)
{
c=a+b;
a=b;
b=c;
printf("\t%d",c);
}
}
getch();
}
Jst Change the for loop
ReplyDeletefor(i=0;i<n-2;i++)
#include
ReplyDeletevoid main()
{ int n,i,a,b,c;
printf("enter the range");
scanf ("%d",&n);
for(i=o;i<=n;i++)
{c=a+b;
a=b;
b=c;
printf("the fibonaci series is=%d",c)
}
getch();
}
logic is correct and simple but it's not working.
ReplyDelete